x^2+(2x-2)=0

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Solution for x^2+(2x-2)=0 equation:


Simplifying
x2 + (2x + -2) = 0

Reorder the terms:
x2 + (-2 + 2x) = 0

Remove parenthesis around (-2 + 2x)
x2 + -2 + 2x = 0

Reorder the terms:
-2 + 2x + x2 = 0

Solving
-2 + 2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '2' to each side of the equation.
-2 + 2x + 2 + x2 = 0 + 2

Reorder the terms:
-2 + 2 + 2x + x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 2x + x2 = 0 + 2
2x + x2 = 0 + 2

Combine like terms: 0 + 2 = 2
2x + x2 = 2

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = 2 + 1

Reorder the terms:
1 + 2x + x2 = 2 + 1

Combine like terms: 2 + 1 = 3
1 + 2x + x2 = 3

Factor a perfect square on the left side:
(x + 1)(x + 1) = 3

Calculate the square root of the right side: 1.732050808

Break this problem into two subproblems by setting 
(x + 1) equal to 1.732050808 and -1.732050808.

Subproblem 1

x + 1 = 1.732050808 Simplifying x + 1 = 1.732050808 Reorder the terms: 1 + x = 1.732050808 Solving 1 + x = 1.732050808 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 1.732050808 + -1 Combine like terms: 1 + -1 = 0 0 + x = 1.732050808 + -1 x = 1.732050808 + -1 Combine like terms: 1.732050808 + -1 = 0.732050808 x = 0.732050808 Simplifying x = 0.732050808

Subproblem 2

x + 1 = -1.732050808 Simplifying x + 1 = -1.732050808 Reorder the terms: 1 + x = -1.732050808 Solving 1 + x = -1.732050808 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = -1.732050808 + -1 Combine like terms: 1 + -1 = 0 0 + x = -1.732050808 + -1 x = -1.732050808 + -1 Combine like terms: -1.732050808 + -1 = -2.732050808 x = -2.732050808 Simplifying x = -2.732050808

Solution

The solution to the problem is based on the solutions from the subproblems. x = {0.732050808, -2.732050808}

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